2x^2+8x=2170

Solution for 2x^2+8x=2170 equation:

2x^2+8x=2170

We move all terms to the left:

2x^2+8x-(2170)=0

a = 2; b = 8; c = -2170;
Δ = b2-4ac
Δ = 82-4·2·(-2170)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-132}{2*2}=\frac{-140}{4}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+132}{2*2}=\frac{124}{4}
=31
$